Jul 16, 2011

[ZT]Using Explicit in C++

In C++ it is possible to declare constructors for a class, taking a single parameter, and use those constructors for doing type conversion. For example:
class A {
        public:
                A(int);
        };

        void f(A) {}

        void g()
        {
                A a1 = 37;

                A a2 = A(47);

                A a3(57);

                a1 = 67;

                f(77);
        }
A declaration like:

A a1 = 37;
says to call the A(int) constructor to create an A object from the integer value. Such a constructor is called a "converting constructor".
However, this type of implicit conversion can be confusing, and there is a way of disabling it, using a new keyword "explicit" in the constructor declaration:
class A {
        public:
                explicit A(int);
        };

        void f(A) {}

        void g()
        {
                A a1 = 37;      // illegal

                A a2 = A(47);   // OK

                A a3(57);       // OK

                a1 = 67;        // illegal

                f(77);          // illegal
        }
Using the explicit keyword, a constructor is declared to be
"nonconverting", and explicit constructor syntax is required:

class A {
        public:
                explicit A(int);
        };

        void f(A) {}

        void g()
        {
                A a1 = A(37);

                A a2 = A(47);

                A a3(57);

                a1 = A(67);

                f(A(77));
        }
Note that an expression such as:
A(47)
is closely related to function-style casts supported by C++. For example:
double d = 12.34;

        int i = int(d);
 
From: http://www.glenmccl.com/tip_023.htm

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